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Nikhil J George

Well here is another mind bender ...

Prove that

            Sinx
Limit  ------- = 6
n->0       n

Easy ... consider the left hand side ...

Cancel n from numerator and denominator (whatever made you think the numerator was sin(x)??) ... that leaves on the Left Hand Side

           
Limit   Si x
n->0       


i.e.

           
Limit   6
n->0       

and that is equal to 6

which is equal to the right hand side Q.E.D

P.S. Many an Indian freshman engineering/math student has been thrown this "problem" during hazing.

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